0=-16x^2+24.25x-4

Solution for 0=-16x^2+24.25x-4 equation:

0=-16x^2+24.25x-4

We move all terms to the left:

0-(-16x^2+24.25x-4)=0

We add all the numbers together, and all the variables

-(-16x^2+24.25x-4)=0

We get rid of parentheses

16x^2-24.25x+4=0

a = 16; b = -24.25; c = +4;
Δ = b2-4ac
Δ = -24.252-4·16·4
Δ = 332.0625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24.25)-\sqrt{332.0625}}{2*16}=\frac{24.25-\sqrt{332.0625}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24.25)+\sqrt{332.0625}}{2*16}=\frac{24.25+\sqrt{332.0625}}{32}
$